如题,本人在网上找到一个parameter pack的例子,如下程序:
#include <iostream> #include <vector> #include <climits> #include <cstdint> #include <type_traits> #include <utility> template<typename ...Args> void printer(Args&&... args) { (std::cout << ... << args) << "\n"; } template<typename T, typename... Args> void push_back_vec(std::vector<T>& v, Args&&... args) { (v.push_back(args), ...); } // compile-time endianness swap based on http://stackoverflow.com/a/36937049 template<class T, std::size_t... N> constexpr T bswap_impl(T i, std::index_sequence<N...>) { return (((i >> N*CHAR_BIT & std::uint8_t(-1)) << (sizeof(T)-1-N)*CHAR_BIT) | ...); }; template<class T, class U = std::make_unsigned_t<T>> constexpr U bswap(T i) { return bswap_impl<U>(i, std::make_index_sequence<sizeof(T)>{}); } int main() { printer(1, 2, 3, "abc"); std::vector<int> v; push_back_vec(v, 6, 2, 45, 12); push_back_vec(v, 1, 2, 9); for (int i : v) std::cout << i << " "; static_assert(bswap<std::uint16_t>(0x1234u)==0x3412u); static_assert(bswap<std::uint64_t>(0x0123456789abcdefULL)==0xefcdab8967452301ULL); }
用g++5.3/6.1编译 g++ -std=c++17 -O2 -Wall -pedantic -pthread main.cpp && ./a.out
都会有下面的编译错误:
main.cpp: In function "constexpr T bswap_impl(T, std::index_sequence<N ...>)": main.cpp:22:49: error: binary expression in operand of fold-expression return (((i >> N*CHAR_BIT & std::uint8_t(-1)) << (sizeof(T)-1-N)*CHAR_BIT) | ...); ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~~ main.cpp: At global scope: main.cpp:23:2: warning: extra ";" [-Wpedantic] };
上面这些是什么意思呢? 没有看懂啊
解决方案
5
clang 3.8 通过
手头没gcc6.x没测试
手头没gcc6.x没测试
10
fold expression的格式是(N4594/expr.prim.fold/Paragraph 1):
不对,括号看岔了……
既然有括号应该就是cast-expression,看来是gcc bug了,怪不得clang能过。