用c语言写一个函数把十进制转换成十六进制 |
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#include “stdio.h”
int main() { int num=0; int a[100]; int i=0; int m=0; int yushu; char hex[16]={“”0″”,””1″”,””2″”,””3″”,””4″”,””5″”,””6″”,””7″”,””8″”,””9″”,””A””,””B””,””C””,””D””,””E””,””F””}; printf(“请输入一个十进制整数:”); scanf(“%d”,&num); while(num>0) { yushu=num%16; a[i++]=yushu; num=num/16; } } 哈哈 简单易懂 |
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输入和输出分别是什么?
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试一下就知道,可以得到正确结果 |
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17分 |
#include <stdio.h> #include <stdlib.h> #include <string.h> #include <locale.h> int main() { int i,v; char bs[33]; char b[33]; char hs[9]; char h[9]; char s[4]; char *e; // 十进制整数转二进制串; i=1024; ltoa(i,b,2); sprintf(bs,"%032s",b); printf("i=%d,bs=%s\n",i,bs); // 十进制整数转十六进制串; i=1024; ltoa(i,h,16); sprintf(hs,"%08s",h); printf("i=%d,hs=%s\n",i,hs); // 十六进制字符串转成十进制数 strcpy(hs,"00000400"); sscanf(hs,"%x",&i); printf("hs=%s,i=%d\n",hs,i); // 二进制字符串转化为十六进制字符串; strcpy(bs,"00000000000000000000010000000000"); i=strtol(bs,&e,2); ltoa(i,h,16); sprintf(hs,"%08s",h); printf("bs=%s,hs=%s\n",bs,hs); // 二进制字符串转化为十进制数; strcpy(bs,"00000000000000000000010000000000"); i=strtol(bs,&e,2); printf("bs=%s,i=%d\n",bs,i); // 十六进制字符串转成二进制串 strcpy(hs,"00000400"); sscanf(hs,"%x",&i); ltoa(i,b,2); sprintf(bs,"%032s",b); printf("hs=%s,bs=%s\n",hs,bs); // ASC\GBK字符串转十六进制串 strcpy(s,"a汉"); i=0; while (1) { if (0==s[i]) break; sprintf(hs+i*2,"%02X",(unsigned char)s[i]); i++; } setlocale(LC_ALL,"chs"); printf("s=%s,hs=%s\n",s,hs); // 十六进制字符串转成汉字(GBK)及字符(ASC) strcpy(hs,"61BABA"); i=0; while (1) { if (1!=sscanf(hs+i*2,"%2x",&v)) break; s[i]=(char)v; i++; } s[i]=0; printf("hs=%s,s=%s\n",hs,s); return 0; } //i=1024,bs=00000000000000000000010000000000 //i=1024,hs=00000400 //hs=00000400,i=1024 //bs=00000000000000000000010000000000,hs=00000400 //bs=00000000000000000000010000000000,i=1024 //hs=00000400,bs=00000000000000000000010000000000 //s=a汉,hs=61BABA //hs=61BABA,s=a汉 |
char pcDec[10]=”123456″;
char pcHex[100]; int iVal; //scanf(“%d”, &iVal); //从键盘输入。 printf(“%d\n%x\n”, iVal, iVal); //分别以10进度和16进制输出到屏幕。 sprintf(pcHex, “%d\n%x\n”, iVal, iVal); //分别以10进度和16进制输出到字符串中。 |
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3分 |
#include <stdio.h> union decompose{ int integer; struct{ unsigned int hex0 : 4; unsigned int hex1 : 4; unsigned int hex2 : 4; unsigned int hex3 : 4; unsigned int hex4 : 4; unsigned int hex5 : 4; unsigned int hex6 : 4; unsigned int hex7 : 4; }hex4; }; /* 此宏定义不能用于循环,即n不能是变量,只能是数字 * 因此比较适用与零散获取位状态或者字节状态 */ #define GETHEX(x, n) (((union decompose){.integer = x}).hex4.hex##n) void test_getx(int tmp) { printf("%X", GETHEX(tmp, 0)); printf("%X", GETHEX(tmp, 1)); printf("%X", GETHEX(tmp, 2)); printf("%X", GETHEX(tmp, 3)); printf("%X", GETHEX(tmp, 4)); printf("%X", GETHEX(tmp, 5)); printf("%X", GETHEX(tmp, 6)); printf("%X\n", GETHEX(tmp, 7)); } int main() { test_getx(100); return 0; } |
搞不懂你要转啥。。。。
整数类型计算机存储本身就是16进制的,有什么转换必要? |
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我的意思和7楼的差不多,输入和输出到底是什么?是字符串还是整型数啊,必须说清楚 |
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上面的连接错了,下面这个可用。
http://download.csdn.net/detail/allenemo/6487471 |
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这个是1000以下十进制转化十六进制的C程序,根据这个别的就不难了~~~~
#include<stdio.h> |
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如此多的解法。。。佩服佩服,谢谢
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