使用CheckedListBox问题整理

码拜

12年 ago

当鼠标移动到滚动条时触发了MouseLeave事件，期待效果为：当鼠标离开CheckedListBox控件区域时触发MouseLeave事件。

最终采用方法：当鼠标进入父控件工作区时，隐藏CheckedListBox控件

获取控件相对父窗体的坐标（不知道是否有更简捷的方法，就递归一下了）

private Point CaculateLocation(Control c) 
        { 
            Control cParent = c.Parent; 
            Point pResult = c.Location; 
            if (cParent is Form) 
            { 
                return pResult; 
            } 
            else
            { 
                Point pParent = CaculateLocation(cParent); 
                return new Point(pResult.X + pParent.X, pResult.Y + pParent.Y); 
            } 
 
        }

创建自定义控件时，判断是否处于设计模式

/// <summary>
/// 指示当前控件是否处于设计模式。
/// </summary>
private new bool DesignMode
{
get
{
bool result = false; // return value
Control ctl = this; // checked control for design mode
do
{
ISite site = ctl.Site; // get the site object, which is set by designer
if (site != null)
{
result = site.DesignMode; // check for design mode
if (result) { break; } // if control is in design mode then loop ends
}
} while ((ctl = ctl.Parent) != null); // track the parent control
//
return result;
}
}

参考链接：http://www.cnblogs.com/deerchao/archive/2007/11/06/950675.html

http://www.codeproject.com/Articles/13584/How-to-avoid-WSODs-in-the-Visual-Studio-2005-Desig