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使用 spring MVC 结合ajax的时候，返回ModelAndView 是 页面无法接受返回值 package com.user.web; import java.util.Date; import javax.servlet.http.HttpServletRequest; import org.springframework.stereotype.Controller; import org.springframework.ui.ModelMap; import org.springframework.web.bind.annotation.RequestMapping; import org.springframework.web.servlet.ModelAndView; import com.jdbc.bean.User; import com.user.service.ITUserSV; import com.zhuangyuan.util.action.BasicAction; @Controller @RequestMapping("/User") public class UserAction extends BasicAction{ @RequestMapping("/Register") public ModelAndView registerUser(HttpServletRequest request,ModelMap mm){ String userName = request.getParameter("userName"); String password = request.getParameter("passWord"); String lastIp = request.getHeader("x-forwarded-for"); Date date = new Date(); User user = new User(); user.setLastIp(lastIp); user.setUserName(userName); user.setPassword(password); user.setLastTime(date); user.setUserId(9L); ModelAndView modelAndView=new ModelAndView("userRegister"); String msg=""; //注册 ITUserSV tUserSV = (ITUserSV)this.getService("tuserSVImpl"); try { tUserSV.insertUser(user); } catch (Exception e) { msg=e.toString(); } msg="注册成功！状元网欢迎你！"; mm.addAttribute("msg", msg); return modelAndView; } } jsp页面：userRegister.jsp <%@ page language="java" import="java.util.*" pageEncoding="GBK"%> <%@ include file="../util/head.jsp"%> <% String path = request.getContextPath(); String basePath = request.getScheme()+"://"+request.getServerName()+":"+request.getServerPort()+path+"/"; %> <script type=""text/javascript"" src=""<%=request.getContextPath() %>/util/jquery/jquery.js""></script> <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"> <html> <head> <base href="<%=basePath%>"> <title>状元网----用户注册</title> <meta http-equiv="pragma" content="no-cache"> <meta http-equiv="cache-control" content="no-cache"> <meta http-equiv="expires" content="0"> <meta http-equiv="keywords" content="keyword1,keyword2,keyword3"> <meta http-equiv="description" content="This is my page"> <!-- <link rel="stylesheet" type="text/css" href="styles.css"> --> </head> <script type="text/javascript"> $(function(){ $(""#commit"").click(function(){ commit(); }); $(""#reset"").click(function(){ reset(); }); $(""#rePassWord"").blur(function(){ if($(""#rePassWord"").val()!=$(""#passWord"").val()){ alert("输入的两次密码不一致!"); $(""#rePassWord"").focus(); return; } }); }); function commit(){ var userName = $(""#userName"").val(); var passWord = $(""#passWord"").val(); if(userName==null||userName==""){ alert("请填写用户名!"); $(""#userName"").focus(); return; } if(passWord==null||passWord==""){ alert("请输入密码!"); $(""#passWord"").focus(); return; } $.ajax({ type:"POST", dataType:""json"", //contentType:"application/json", cache:false, data:"userName="+userName+"&passWord="+passWord, url:"<%=request.getContextPath() %>/User/Register.do?formart=json", success:function(data){ aler(data.msg); }, error:function(data){ alert("注册失败，系统错误："+data); } }); } function reset(){ $(""#userName"").val(""); $(""#passWord"").val(""); $(""#rePassWord"").val(""); } </script> <body> <center> <table> <tr> <td>用 户 名:</td> <td><input id="userName"/></td> </tr> <tr> <td>密 码:</td> <td><input type="password" id="passWord"/></td> </tr> <tr> <td>再次确定密码:</td> <td><input type="password" id="rePassWord"/></td> </tr> <tr> <td><a id="commit">提交</a></td> <td><a id="reset"/>取消</a></td> </tr> </table> </center> </body> </html> servlet配置文件 <?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:p="http://www.springframework.org/schema/p" xmlns:context="http://www.springframework.org/schema/context" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.1.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.1.xsd"> <context:component-scan base-package="com.user.web"></context:component-scan> <bean class="org.springframework.web.servlet.view.ContentNegotiatingViewResolver" p:defaultContentType="text/html" p:favorPathExtension="false" p:favorParameter="true" p:ignoreAcceptHeader="true" > <property name="mediaTypes"> <map> <entry key="html" value="text/html"/> <entry key="xml" value="application/xml" /> <entry key="json" value="application/json" /> </map> </property> <property name="defaultViews"> <list> <bean class="org.springframework.web.servlet.view.json.MappingJacksonJsonView"></bean> <!-- <bean class="org.springframework.web.servlet.view.xml.MarshallingView" p:modelKey="msg" p:marshaller-ref="xmlMarshaller"></bean> --> </list> </property> </bean> <bean class="org.springframework.web.servlet.view.InternalResourceViewResolver" p:order="10" p:viewClass="org.springframework.web.servlet.view.JstlView" p:prefix="/user/" p:suffix=".jsp" > </bean> </beans> 当点击提交按钮的时候 ，数据库中可以新增一条记录，但是在返回的时候，执行的却是 ajax中的 error 函数！ |
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说明你的service业务做了，但是返回数据给前台的时候出错了
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后台肯定报错了，你看下异常信息，或者你再用firebug看下错误信息
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看控制台 |
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不要看js。。
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赶紧试我的Serverlet配置文件出了问题，但是没有把握！ |
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看控制台的错误啊 |
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$.post(“”<%=request.getContextPath() %>/User/Register.do?formart=json””,{“”userName””:userName,””passWord””:passWord}, function(data){
aler(data.msg); } |
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jquery 错误信息可以打印出来 。
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楼主，你的跳转方式不对吧，应该是用相应的方式哦….
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打错了，
@RequestMapping(“/Register”) 这个要改成response方式的吧… |
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return modelAndView 这样会导致重新跳转页面，ajax肯定会error了
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ajxa请求返回是void，是print()到前台的，
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CodeBye 版权所有丨如未注明 , 均为原创丨本网站采用BY-NC-SA协议进行授权 , 转载请注明spring MVC 结合 ajax 返回错误！
