# include <stdio.h>
# define N 100
char htoi(char s[]);
int main()
{
char a[N];
printf(“请输入十六进制数的字符串”);
gets(a);
htoi(a);
printf(“十进制数为:%d”, htoi(a));
return 0;
}
char htoi(char s[])
{
int i;
int n;
int sum;
sum = 0;
for (i = 0; s[i] != “”\0″”; i++)
{
if (s[i] >= “”0″” || s[i] <= “”9″”)
n = s[i] – “”0″”;
if (s[i] >= “”a”” || s[i] <= “”z””)
n = s[i] – 87;
if (s[i] >= “”A”” || s[i] <= “”Z””)
n = s[i] – 55;
sum = 16 * sum + n;
}
return sum;
}
帮本人看一下本人这代码错哪了,改代码是为了实现将十六进制数转化成十进制,0x为开头的十六进制数也可实现
# define N 100
char htoi(char s[]);
int main()
{
char a[N];
printf(“请输入十六进制数的字符串”);
gets(a);
htoi(a);
printf(“十进制数为:%d”, htoi(a));
return 0;
}
char htoi(char s[])
{
int i;
int n;
int sum;
sum = 0;
for (i = 0; s[i] != “”\0″”; i++)
{
if (s[i] >= “”0″” || s[i] <= “”9″”)
n = s[i] – “”0″”;
if (s[i] >= “”a”” || s[i] <= “”z””)
n = s[i] – 87;
if (s[i] >= “”A”” || s[i] <= “”Z””)
n = s[i] – 55;
sum = 16 * sum + n;
}
return sum;
}
帮本人看一下本人这代码错哪了,改代码是为了实现将十六进制数转化成十进制,0x为开头的十六进制数也可实现
解决方案:10分
仅供参考:
#include <stdio.h> #include <stdlib.h> #include <string.h> #include <locale.h> int main() { int i,v; char bs[33]; char b[33]; char hs[9]; char h[9]; char s[4]; char *e; // 十进制整数转二进制串; i=1024; ltoa(i,b,2); sprintf(bs,"%032s",b); printf("i=%d,bs=%s\n",i,bs); // 十进制整数转十六进制串; i=1024; ltoa(i,h,16); sprintf(hs,"%08s",h); printf("i=%d,hs=%s\n",i,hs); // 十六进制字符串转成十进制数 strcpy(hs,"00000400"); sscanf(hs,"%x",&i); printf("hs=%s,i=%d\n",hs,i); // 二进制字符串转化为十六进制字符串; strcpy(bs,"00000000000000000000010000000000"); i=strtol(bs,&e,2); ltoa(i,h,16); sprintf(hs,"%08s",h); printf("bs=%s,hs=%s\n",bs,hs); // 二进制字符串转化为十进制数; strcpy(bs,"00000000000000000000010000000000"); i=strtol(bs,&e,2); printf("bs=%s,i=%d\n",bs,i); // 十六进制字符串转成二进制串 strcpy(hs,"00000400"); sscanf(hs,"%x",&i); ltoa(i,b,2); sprintf(bs,"%032s",b); printf("hs=%s,bs=%s\n",hs,bs); // ASC\GBK字符串转十六进制串 strcpy(s,"a汉"); i=0; while (1) { if (0==s[i]) break; sprintf(hs+i*2,"%02X",(unsigned char)s[i]); i++; } setlocale(LC_ALL,"chs"); printf("s=%s,hs=%s\n",s,hs); // 十六进制字符串转成汉字(GBK)及字符(ASC) strcpy(hs,"61BABA"); i=0; while (1) { if (1!=sscanf(hs+i*2,"%2x",&v)) break; s[i]=(char)v; i++; } s[i]=0; printf("hs=%s,s=%s\n",hs,s); return 0; } //i=1024,bs=00000000000000000000010000000000 //i=1024,hs=00000400 //hs=00000400,i=1024 //bs=00000000000000000000010000000000,hs=00000400 //bs=00000000000000000000010000000000,i=1024 //hs=00000400,bs=00000000000000000000010000000000 //s=a汉,hs=61BABA //hs=61BABA,s=a汉
解决方案:10分
if (s[i] >= “”0″” || s[i] <= “”9″”)
应该是用&&而不是 || 吧,其他几个if中的也对应改了
应该是用&&而不是 || 吧,其他几个if中的也对应改了
解决方案:20分
另外,htoi的返回值应该是int不是char吧
# include <stdio.h> # define N 100 int htoi(char s[]); int main() { char a[N]; printf("请输入十六进制数的字符串"); gets(a); htoi(a); printf("十进制数为:%d", htoi(a)); return 0; } int htoi(char s[]) { int i; int n; int sum; sum = 0; for (i = 0; s[i] != ""\0""; i++) { if (s[i] >= ""0"" && s[i] <= ""9"") n = s[i] - ""0""; else if (s[i] >= ""a"" && s[i] <= ""z"") n = s[i] - 87; else if (s[i] >= ""A"" && s[i] <= ""Z"") n = s[i] - 55; sum = 16 * sum + n; } return sum; }