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1.#include<stdio.h> main() |
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| 10分 |
1.修改如下：
#include<stdio.h>
void fun(char x[5][10], int n)
{
x[n][0] = 0;
}
int main()
{
char x[5][10] = { "create","modify","sort","skip","delete" };
int i;
printf("the original string:\n");
for (i = 0; i<5; i++)
puts(x[i]);
printf("\n");
printf("the string after delect:\n");
fun(x, 4);
for (i = 0; i<5; i++)
puts(x[i]);
printf("\n");
return 0;
}
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| 10分 |
2.这样可好：
int i, pos1, pos2, n;
unsigned char bm[32];
int main(void)
{
char *s = "beijing";
n = strlen(s);
memset(bm, 0, 32);
for (i = 0; i < n; i++)
{
pos1 = s[i] / 8;
pos2 = s[i] % 8;
if (0 == (bm[pos1] & (1u << pos2)))
{
bm[pos1] |= 1u << pos2;
}
else
{
printf("%c\n", s[i]);
break;
}
}
if (i == n) printf("non a character occurs twice!\n");
return 0;
}
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| 10分 |
正确来讲，是第一个出现两次以上的字符
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另一个问题
#include<stdio.h> char *fun(char *p) { int i,j=0; char *q=p; for(i=0;i<20;i++) { if(“”0″”<=q[i]&&q[i]<=””9″”) p[j++]=q[i]; } for(i=0;i<20;i++) { if(“”0″”<=q[i]&&q[i]<=””9″”) continue; else p[j++]=q[i]; } return(p);//为什么不能返回局部变量q的地址 return(q);//为什么不能返回局部变量q的地址,如果在前一句加p=q；返回q也是错误的，为什么？ char s[20]=”asd123fgh5##43df”;//为什么输出为123543fgh##df printf(“%s\n”,b); |
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| 10分 |
char *q=p; // 这样写 return q; |