设红、花、映、绿、叶、春都是一个10以内的整数，其中“红花映绿叶”组成一个五位整数。若“红花映绿叶X春=叶绿映花红”，问一下红花映绿叶春分别是什么数。
解决方案
15
答案简直太多了。
笨办法：
笨办法：
int hong,hua,ying,lv,ye,chun = 0;
string mes = "";
for (hong = 1; hong < 10; hong++)
{
for (hua = 1; hua < 10; hua++)
{
for (ying = 1; ying < 10; ying++)
{
for (lv = 1; lv < 10; lv++)
{
for (ye = 1; ye < 10; ye++)
{
for (chun = 1; chun < 10; chun++)
{
int a = hong * 10000 + hua * 1000 + ying * 100 + lv * 10 + ye;
int b = ye * 10000 + lv * 1000 + ying * 100 + hua * 10 + hong;
if (a * chun == b)//红花映绿叶X春=叶绿映花红
{
if (mes != "")
mes += ",红" + hong + ",花" + hua + ",映" + ying + ",绿" + lv + ",叶" + ye + ",春" + chun;
else
mes += "红" + hong + ",花" + hua + ",映" + ying + ",绿" + lv + ",叶" + ye + ",春" + chun;
}
}
}
}
}
}
}
MessageBox.Show(mes);
15
int count = 1;
string 红 = string.Empty, 花 = string.Empty, 映 = string.Empty, 绿 = string.Empty, 叶 = string.Empty, 春 = string.Empty;
for (int a = 0; a < 10; a++)
{
for (int b = 0; b < 10; b++)
{
for (int c = 0; c < 10; c++)
{
for (int d = 0; d < 10; d++)
{
for (int e = 0; e < 10; e++)
{
for (int f = 0; f < 10; f++)
{
红 = a.ToString();
花 = b.ToString();
映 = c.ToString();
绿 = d.ToString();
叶 = e.ToString();
春 = f.ToString();
int result = int.Parse(红 + 花 + 映 + 绿 + 叶) * int.Parse(春);
if (result == int.Parse(叶 + 绿 + 映 + 花 + 红))
{
Console.WriteLine(string.Format("红:{0} 花 :{1} 映 :{2} 绿 :{3} 叶:{4} 春:{5} 计数：{6}", 红, 花, 映, 绿, 叶, 春, count));
count++;
}
}
}
}
}
}
}
Console.Read();
