情况是这样的,现在有客户端用C#写的,然后调用webservice,服务端不知道是java还是C#或其他语言写的。
C#这边调用webservice的代码是:
C#这边调用webservice的代码是:
var xmlStr = new WSInterfacePortTypeClient().CallInterface(msgHeader, babyInfoStr);
返回xml串。
然后C#这边的配置文件是这样的,在app.config中的配置是这样的:
<?xml version="1.0" encoding="utf-8" ?> <configuration> <system.serviceModel> <bindings> <basicHttpBinding> <binding name="WSInterfaceSoap11Binding" closeTimeout="00:00:10" openTimeout="00:00:10" receiveTimeout="00:00:10" sendTimeout="00:00:10" maxBufferPoolSize="655360000000" maxBufferSize="655360000" maxReceivedMessageSize="655360000000" transferMode="Streamed"> <readerQuotas maxDepth="64" maxStringContentLength="655360000" maxArrayLength="655360000" maxBytesPerRead="655360000" maxNameTableCharCount="655360000" /> <security mode="None" /> </binding> </basicHttpBinding> </bindings> <client> <endpoint address="http://168.2.5.28:1506/services/WSInterface.WSInterfaceHttpSoap11Endpoint" binding="basicHttpBinding" bindingConfiguration="WSInterfaceSoap11Binding" contract="HisReferance.WSInterfacePortType" name="WSInterfaceHttpSoap11Endpoint" /> </client> </system.serviceModel> <startup> <supportedRuntime version="v4.0" sku=".NETFramework,Version=v4.5" /> </startup>
现在想用java来重写,但是网上查了下,一般都需要知道一个地址,例如http://x.x.x.x/service/abc.asmx,现在的疑问是
endpoint address=”http://168.2.5.28:1506/services/WSInterface.WSInterfaceHttpSoap11Endpoint 的后缀并不是.asmx,
而且这句:
var xmlStr = new WSInterfacePortTypeClient().CallInterface(msgHeader, babyInfoStr);能说明服务端的方法名就是
CallInterfacea吗?
不知道有没有对这个了解的?求指导。
解决方案
80
CallInterface只是调用接口的方法,真正的接口名称在参数中
20
尝试一下:
http://168.2.5.28:1506/services/WSInterface.WSInterface.asmx 或: http://168.2.5.28:1506/services/WSInterface.asmx